(0.15x+x^2)/(4-4x+x^2)

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Solution for (0.15x+x^2)/(4-4x+x^2) equation: 


D( x )

x^2-(4*x)+4 = 0

x^2-(4*x)+4 = 0

x^2-(4*x)+4 = 0

x^2-4*x+4 = 0

x^2-4*x+4 = 0

DELTA = (-4)^2-(1*4*4)

DELTA = 0

x = 4/(1*2)

x = 2 or x = 2

x in (-oo:2) U (2:+oo)

(x^2+0.15*x)/(x^2-(4*x)+4) = 0

(x^2+0.15*x)/(x^2-4*x+4) = 0

x^2+0.15*x = 0

x*(x+0.15) = 0

x+0.15 = 0 // - 0.15

x = -0.15

x*(x+0.15) = 0

x^2-4*x+4 = 0

x^2-4*x+4 = 0

DELTA = (-4)^2-(1*4*4)

DELTA = 0

x = 4/(1*2)

x = 2 or x = 2

(x-2)^2 = 0

(x*(x+0.15))/((x-2)^2) = 0

( x+0.15 )

x+0.15 = 0 // - 0.15

x = -0.15

( x )

x = 0

x in { -0.15, 0 }

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